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sicp-all-tasks/sicp/1_002e41

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Exercise 1.41: Define a procedure double
that takes a procedure of one argument as argument and returns a procedure that
applies the original procedure twice. For example, if inc is a
procedure that adds 1 to its argument, then (double inc) should be a
procedure that adds 2. What value is returned by
(((double (double double)) inc) 5)