Exercise 1.6: Alyssa P. Hacker doesn’t see why
if needs to be provided as a special form.  “Why can’t I just define it
as an ordinary procedure in terms of cond?” she asks.  Alyssa’s friend
Eva Lu Ator claims this can indeed be done, and she defines a new version of
if:


(define (new-if predicate 
                then-clause 
                else-clause)
  (cond (predicate then-clause)
        (else else-clause)))

Eva demonstrates the program for Alyssa:


(new-if (= 2 3) 0 5)
5

(new-if (= 1 1) 0 5)
0


Delighted, Alyssa uses new-if to rewrite the square-root program:


(define (sqrt-iter guess x)
  (new-if (good-enough? guess x)
          guess
          (sqrt-iter (improve guess x) x)))

What happens when Alyssa attempts to use this to compute square roots?
Explain.